once again substitution! can anyone help?
x/y-y/3=5/6
x/5-y/4=-13/10
solve by substitution
same thing as "Archi meade" wrote there, just now with different numbers
multiply firs with 6 and second with 20
now i u can go as you wish
first one multiply with 4 and second with (-3) (and then sum them )
rest you know
or u can :
and put in second and solve for "y" and so on for x...
P.S. you don't need to do that this way (that's up to you, and with practice u can decide better how and what would you do, so that you have a less work, and to keep it simple... don't complicate it to much )
Edit: corrected that "6" and "20"... i really don't know from where and when did i type that
here's using substitution :
first one multiply with (6) and second with (20) and you will get :
now from any ( i'll do first ) you can express either "x" or "y" (i'll do "x" )
now that "x we put in second equation ...
now multiply with 3 :
now that "y" we will put in first equation
P.S. what ? now second equation is with -71/10 , where did go -13/10 ?