1. ## Inequality

Solve the inequality...

x^2 + 6x + 5 > 0

2. $x^2+6x+5 = (x+1)(x+5)$

What now?

3. Originally Posted by MATNTRNG
Solve the inequality...

x^2 + 6x + 5 > 0

$(x+1)(x+5)>0$

$x>-1 \; \; \; x<-5$

Edit: Sorry "pickslides" i didn't refresh thread

4. I do not understand why we flip the inequality sign to get x < -5

5. Originally Posted by MATNTRNG
I do not understand why we flip the inequality sign to get x < -5
(x+5)(x+1) > 0

critical values are x = -5 and x = -1

values of x < -5 make the inequality true.

values of x between and including x = -1 and x = -5 make the inequality false.

values of x > -1 make the inequality true.

alternatively, think about the graph of y = (x+5)(x+1) ... for what values of x is the value of y > 0 ?