for #2, i got:
3(x-3)/(x+3)(x-3)(x-3) + 4(x+3)(x-3)/(x-3)(x+3)
3(x-3) + 4(x^2-9)/x^2-9(x^2-9)
is that wrong?
1- divide using long division (9x^3-9x^2-x-12) / (3x-5)
2- simplify 3/x^2-9 + 4/x-3
3- given the polynomial x^3-5x^2+2x+8 where x-4 is a factor. find another factor
4- simplify 4x^5y^-3 / 20x^-2y
*****
sorry if the math is messy, but I don't know the code to make it nice.
i don't know how to type up the long division, so try it and come up with an answer and i'll tell you if its right.
you don't have to know the codes (though they are not that hard, i started learning them just today, and i'm doing pretty well i think) but you can use parenthesis to simplify. is this what you mean?
2- simplify 3/x^2-9 + 4/x-3
Simplify
think of other factors of 8 and plug them into the formula, if the result is zero, then x - the thing you plugged in is a factor.
3- given the polynomial x^3-5x^2+2x+8 where x-4 is a factor. find another factor
again, use parenthesis
4- simplify 4x^5y^-3 / 20x^-2y
should it be, simplify ?
Hello,
to #1:to #2:Code:(9x³ - 9x² - x - 12) ÷ (3x - 5) = 3x² + 2x + 3 (3x³ - 15x²) ------------- 6x² - x 6x² - 10x --------- 9x - 12 9x - 15 -------- 3 ← remainder
to #3:
a) use long division
b) use synthetic divisionThat means:Code:| 1 -5 2 8 | 0 4 -4 -8 ------|---------------- x = 4 | 1 -1 -2 0
The last factor can be factorized again so that you finally have:
to #4:
It's going to be kind of hard to explain this one. i'll do the problem by hand and try to scan a copy and hopefully you'll be able to figure it out from that.
....the LCD is (x + 3)(x - 3)2- simplify 3/x^2-9 + 4/x-3
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By the rational roots theorem, the possible rational roots are given by the factors of 8 are: , , ,3- given the polynomial x^3-5x^2+2x+8 where x-4 is a factor. find another factor
start with and start plugging in each of the factors of 8 into the formula, if we get zero as the result, we have a root.
we realize that -1 works, since,
since x = -1 is a root, it means x + 1 is a factor by the factor theorem
4- simplify 4x^5y^-3 / 20x^-2y
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EDIT: Thanks a lot earboth. anyway, i guess it's my own fault for going around asking a lot of questions before doing the problem