You need to use the equation distance = rate * time.
We know that
and
Solve for r. that will be the rate of runner 2.
I'll even set it up for you.
Solve for t
Plug this value in for t in equation 1
Foil it
Combine like terms
Multiply through by an r
Divide by 10
Solve the quadratic. You will get two rates. One will be the rate for runner 1. The other will be the rater for runner 2.
25 and 20??? is that how easy it is???? but why does my formula doesnt work the way it should be???
distace rate time
faster 1500 ft x+5 1500/x+5
slower 1000 ft X 1000 / x
equation: distance of faster is equal to distance travveled by slower:
1500/ x +5 = (1000 / x) + 10
plus 10 to make the slower runner distance 1500 feet also... why my equation doesnt work?? but its correct right?