it took a faster runner 10 seconds longer to run a distance of 1500 ft. Then it took a slower runner to run 1000 ft. If the rate of faster runner was 5 feet per second more than the slower runner, what was the rate of each runner
I'll even set it up for you.
Solve for t
Plug this value in for t in equation 1
Combine like terms
Multiply through by an r
Divide by 10
Solve the quadratic. You will get two rates. One will be the rate for runner 1. The other will be the rater for runner 2.
25 and 20??? is that how easy it is???? but why does my formula doesnt work the way it should be???
distace rate time
faster 1500 ft x+5 1500/x+5
slower 1000 ft X 1000 / x
equation: distance of faster is equal to distance travveled by slower:
1500/ x +5 = (1000 / x) + 10
plus 10 to make the slower runner distance 1500 feet also... why my equation doesnt work?? but its correct right?