given that $\displaystyle 2x^3-3x^2-11x+6=(x+2)(2x-1)(x-3)$, solve the equation $\displaystyle 2-3x-11x^2+6x^3=0$
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$\displaystyle 2 - 3x - 11x^2 + 6x^3 = 0$ $\displaystyle x^3(2x^{-3} - 3x^{-2} - 11x^{-1} + 6) = 0$ Now let $\displaystyle X = x^{-1}$ to give $\displaystyle x^3(2X^3 - 3X^2 - 11X + 6) = 0$. Go from here.
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