if y >= 0, what is the value of x? |x-3| <= -y Very confused with this one. Can anyone give me some good hints?
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Originally Posted by thumpin_termis if y >= 0, what is the value of x? |x-3| <= -y Very confused with this one. Can anyone give me some good hints? Hello, |x-3| > 0 for x != (means unequal) 3 if y > 0 the RHS of the inequality is lower than zero. There is only one possibility that this inequality is satisfied: If x = 3 and y = 0
Originally Posted by thumpin_termis if y >= 0, what is the value of x? |x-3| <= -y Very confused with this one. Can anyone give me some good hints? If y>=0 then -y<=0. If -y<= then no matter what x you chose it will work because |x-3|>=0. So -y=0. Meaning |x-3| = 0 so, x=3
Great. Thanks guys.
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