x power 4 -(x-z)whole power 4.
Factorisation
I guess that you are expected to use the difference of two squares resultOriginally Posted by shaurya
here:
$\displaystyle u^2-v^2=(u-v)(u+v)$.
Here you have:
$\displaystyle x^4-(x-z)^4$.
Now use $\displaystyle x^2$ for $\displaystyle u$ and $\displaystyle (x-z)^2$ for $\displaystyle v$, this will give you the first stage
of factorisation. The difference of squares can then be applied again to further.
factorise the expression.
RonL