x power 4 -(x-z)whole power 4.

Factorisation

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- Dec 30th 2005, 05:45 AMshauryaAlgebra
x power 4 -(x-z)whole power 4.

Factorisation - Dec 30th 2005, 07:55 AMCaptainBlackQuote:

Originally Posted by**shaurya**

here:

$\displaystyle u^2-v^2=(u-v)(u+v)$.

Here you have:

$\displaystyle x^4-(x-z)^4$.

Now use $\displaystyle x^2$ for $\displaystyle u$ and $\displaystyle (x-z)^2$ for $\displaystyle v$, this will give you the first stage

of factorisation. The difference of squares can then be applied again to further.

factorise the expression.

RonL