1. ratios

Find A:B, if (2A+4B)/(2A-4B) =3/2

2. Find A:B, if (2A+4B)/(2A-4B) =3/2
Hello,
(scratch what was there before)

You could just cross-multiply :

$\displaystyle 2(2A + 4B) = 3(2A - 4B)$

Then expand :

$\displaystyle 4A + 8B = 6A - 12B$

Simplify :

$\displaystyle 20B = 2A$

Simplify again :

$\displaystyle 10B = A$

Finally :

$\displaystyle 10 = \frac{A}{B}$

Does it make sense ?

3. 2a+4b=3

&

2a-4b=2

4. Originally Posted by sfspitfire23
Find A:B, if (2A+4B)/(2A-4B) =3/2

which is fine as the numerator is one and a half times the denominator.

then $\displaystyle 2A-2A+4B=3A-2A-6B\ \Rightarrow\ 4B=A-6B$

$\displaystyle 4B+6B=A+6B-6B=A$

$\displaystyle 10B=A\ \Rightarrow\ 10=\frac{A}{B}\ \Rightarrow\ A:B=10:1$

Or...

$\displaystyle \frac{2A+4B}{2A-4B}=\frac{3}{2}\ \Rightarrow\ \frac{2(2A+4B)}{2A-4B}=3$

$\displaystyle \Rightarrow\ 4A+8B=3(2A-4B)\ \Rightarrow\ 4A+8B=6A-12B$

$\displaystyle 20B=2A$

5. Thanks Archie, for making me notice a typo in my post (fixed by the way). Enough math for me for today - too much mistakes.
Nice working also