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Thread: Factorization

  1. #1
    Member kjchauhan's Avatar
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    Factorization

    Please help me, How to factorise this polynomial...

    $\displaystyle D^5-13D^3+26D^2+82D+104=0$

    Thanks in advance...
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  2. #2
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    Find the positive and negative factors of $\displaystyle 104$.

    Then substitute each of these into the polynomial.

    If any of them (call it $\displaystyle a$) gives you $\displaystyle 0$ after simplifying the left hand side, then $\displaystyle (x - a)$ is a factor.

    After you've done that, long divide, follow the same process.
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  3. #3
    Member kjchauhan's Avatar
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    Quote Originally Posted by Prove It View Post
    Find the positive and negative factors of $\displaystyle 104$.

    Then substitute each of these into the polynomial.

    If any of them (call it $\displaystyle a$) gives you $\displaystyle 0$ after simplifying the left hand side, then $\displaystyle (x - a)$ is a factor.

    After you've done that, long divide, follow the same process.
    I found a factor $\displaystyle D+4$, but I can not find the facors of other factor $\displaystyle D^4-4D^3+3D^2+14D+26$.
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  4. #4
    Super Member Bacterius's Avatar
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    Hint : plot your polynomial and have a look at it. Then you should understand why you can't find other factors
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  5. #5
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    You've found the only real root of f(x)=0.
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