Yes, you are "tackling this completely wrong". First recognize that so your equation is the same as . If you let your equation becomes . Solve that quadratic equation for y, then use logarithms to solve .What do you put in the middle: log(3^(2x)) ? log(3^x) = log(20) or am i tackling this completely wrong?
No matter how I change/re-arrange the equation, I can't seem to get rid of the plus to put logs into it