Thread: Help Needed in Graphing Equations

I honestly don't know what I would do without this forum. This time, I am stumped by a graphing problem with equations. The question is...

Graph the equation 3y = 2x + 5 and calculate slope, x-intercept and y-intercept.

I have been working on this one problem for a while now and so far, I have deciphered that the x and y intercept is x=-5/2 and y=5/3...is that correct? If that is correct, then the slope should be 1...again if I am doing it right.

As always, any help would be greatly appreciated.

Originally Posted by dclary

I have been working on this one problem for a while now and so far, I have deciphered that the x and y intercept is x=-5/2 and y=5/3...is that correct?

They are correct.

Originally Posted by dclary

If that is correct, then the slope should be 1...again if I am doing it right.

The slope is not 1. You need to use the points you just found to find or find the eqn in the form

Hi Pickslides, thank you. To graph the equation for x=-5/2, I would go left 5 and up 2...right? and for the y=5/3, I would go up 5 and across to 3? I just want to make sure I am headed in the right direction. Thank you again for your help.

Originally Posted by dclary

Hi Pickslides, thank you. To graph the equation for x=-5/2, I would go left 5 and up 2...right? and for the y=5/3, I would go up 5 and across to 3? I just want to make sure I am headed in the right direction. Thank you again for your help.

No this is not correct. Draw your x and y axis, then mark the respective values you have found on each axis.

Your points are and and

Now find the gradient using

I finally got it figured out...thank you again Pickslides :-)