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Math Help - Help Needed in Graphing Equations

  1. #1
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    Help Needed in Graphing Equations

    I honestly don't know what I would do without this forum. This time, I am stumped by a graphing problem with equations. The question is...

    Graph the equation 3y = 2x + 5 and calculate slope, x-intercept and y-intercept.

    I have been working on this one problem for a while now and so far, I have deciphered that the x and y intercept is x=-5/2 and y=5/3...is that correct? If that is correct, then the slope should be 1...again if I am doing it right.

    As always, any help would be greatly appreciated.


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  2. #2
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    Quote Originally Posted by dclary View Post

    I have been working on this one problem for a while now and so far, I have deciphered that the x and y intercept is x=-5/2 and y=5/3...is that correct?
    They are correct.

    Quote Originally Posted by dclary View Post
    If that is correct, then the slope should be 1...again if I am doing it right.
    The slope is not 1. You need to use the points you just found to find m = \frac{y_2-y_1}{x_2-x_1} or find the eqn in the form y=mx+c
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  3. #3
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    Hi Pickslides, thank you. To graph the equation for x=-5/2, I would go left 5 and up 2...right? and for the y=5/3, I would go up 5 and across to 3? I just want to make sure I am headed in the right direction. Thank you again for your help.
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  4. #4
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    Quote Originally Posted by dclary View Post
    Hi Pickslides, thank you. To graph the equation for x=-5/2, I would go left 5 and up 2...right? and for the y=5/3, I would go up 5 and across to 3? I just want to make sure I am headed in the right direction. Thank you again for your help.
    No this is not correct. Draw your x and y axis, then mark the respective values you have found on each axis.

    Your points are and \left(x_1,y_1\right) = \left(\frac{-5}{2},0\right) and \left(x_2,y_2\right) = \left(0, \frac{5}{3}\right)

    Now find the gradient using m = \frac{y_2-y_1}{x_2-x_1}
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  5. #5
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    I finally got it figured out...thank you again Pickslides :-)
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