"solve the following equation for x"
4^(3x-2) = 26^(x+1)
i use logs and get to :
(3x-2)log4 = (x+1)log26 ...but not sure where to go from here...simple I imagine.
thanks
"log 4" and "log 26" are just numbers. If it were (3x- 2)A= (x+ 1)B for A and B any numbers, you would multiply to get 3Ax- 2A= Bx+ B. Subtract Bx from both sides and add 2A to both sides to get (3A- B)x= B+ 2A. Finally, (as long as ) divide both sides by 3A- B to get . Now, replace A by log 4 and replace B by log 26.
Hello, porge111!
Solve for
i used logs and get to: .
... but not sure where to go from here.
You have: .
. . . . . . .
Factor: .
Therefore:. . . . . . . . . . . .
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
This can be simplified beyond all recognition . . .
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