2^7 = 128. So...
It's funny yes but I was merely following the instructions of the problem (or trying to do so, since the problem doesn't make much sense); given freedom, I would also use the approximation 2^10 10^3.
Anyway if you go high enough, 2^10 10^3 will give you 99.99% error as well.
[QUOTE=1005;539205]undefined's approximation(10^96) is 5 order of magnitude off with 99.99% error (lol)
and Soroban's approximation is 1 order of magnitude off with 54.28% error.[/QUOTE
Soroban's approx is not one magnitude off. It can be expressed as 0.64E101. Calculator answer is 1.4xE 101
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