If only log(2) and log(3) are given, then how can I calculate log(20) and log(30) ?
(The base is 10)
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I believe you need too, since and .
Originally Posted by Bacterius I believe you need too, since and . ... if the base is , then is ... but more simple is and ...
Originally Posted by chisigma ... if the base is , then is ... but more simple is and ...
Thanks a lot... that helps !
Actually, you don't need log(5). log(30)= log(3(10))= log(3)+ log(10) and log(20)= log(2(10))= log(2)+ log(10)- and you know log(10).
(Which I notice now is exactly what chi sigma said!)
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