# Thread: Word problem - Can anybody give me a hand?

1. ## Word problem - Can anybody give me a hand?

50 students attend school. School has two popular classes: cooking and oil painting. Enrollment in the cooking class is 38 students, and enrollment into oil painting class is 34. If there are 6 students who take neither, how many students take both?

2. There are a total of 50 students and only 6 of them do not take either class. That leaves 50- 6= 44 students who take one or both of those classes.

We are told that there are 38 students in the cooking class and 34 in the painting class. My goodness, 38+ 34= 72 which is larger than 44! How do you suppose that could happen?

3. I am thinking that 28 students attend both.... 72-44=28
10 attend paining class and 6 attend cooking only...

4. You mean 10 attend cooking and 6 attend painting class only

5. Yes. Thanks for pointing this out.

6. students that doesnt take cooking class = 50 - 38 = 12

students that doesnt take oil painting class = 50 - 34 =16

students that doesnt take both = 6

therefore ,the stdent that take both = 50 - 6 - 16 - 12 = 16

you can check by adding all of the students = 16 + 12 + 6+ 16 = 50

7. Originally Posted by Zharif93
students that doesnt take cooking class = 50 - 38 = 12
students that doesnt take oil painting class = 50 - 34 =16
students that doesnt take both = 6
therefore ,the stdent that take both = 50 - 6 - 16 - 12 = 16
you can check by adding all of the students = 16 + 12 + 6+ 16 = 50
Sorry, but that doesn't work. The "students that don't take cooking" includes those "students who don't take either"- you cannot add them separately. If there were 16 students taking both classes then there would be 38- 16= 22 students taking cooking only and 34- 16= 18 students taking painting only. That would give a total of 22+ 18+ 16+ 6= 62 students which is impossible.

There are 28 students who take both, as Angie80 said, so 38- 28= 10 students who take cooking only and 34- 28= 6 students who take painting only.

That gives a total of 10+ 6+ 28+ 6= 50 students.

8. learning how to do Venn diagrams will serve you well ...

How to Do Venn Diagram Problems: Math Lessons | eHow.com