"Solve for x:"
2 X 3^2x+3 = 3 X 2^3x+4
(X is multiply)
feel silly for posting this, is a simple log question i think, but its got me stumped.
thanks
well several ways to solve this..
but you can divide both sides by $\displaystyle 2^1$ and $\displaystyle 3^1$ to elimate the coeficients,
then
$\displaystyle 3^{2x+2} = 2^{3x+3}
\Rightarrow
(2x+2)\ln{3} = (3x+3)\ln{2}
\Rightarrow
\frac{2x+2}{3x+3} = \frac{\ln{2}}{\ln{3}}
$
after calculation we are left with
$\displaystyle x(.107) = -.107\Rightarrow x= -1$