"Solve for x:"
2 X 3^2x+3 = 3 X 2^3x+4
(X is multiply)
feel silly for posting this, is a simple log question i think, but its got me stumped.
Follow Math Help Forum on Facebook and Google+
Just to clarify, you want to solve Is that correct? If so, what steps have you taken?
it could be also:
in which case
sorry yeah the above is the way it's laid out - how did you get -1 ?
well several ways to solve this..
but you can divide both sides by and to elimate the coeficients,
after calculation we are left with
Last edited by bigwave; July 15th 2010 at 01:05 PM.
Reason: added steps
ahhh it's so simple, i'm so stupid. haha thanks, i just didn't start with the basic, "dividng by 2" part. oops.
2(3)^2x+3 = 3(2)^3x+4
log 2 × log 3^(2x+3) = log 3 × log 2^(3x+4)
(2x+3) log 3 = log 3
(3x+4) log 2 = log 2
2x log 3 + 3 log = log 3
2x log 3 = log 3 - 3 log 3
x(2 log 3) = -2 log 3
x = -2 log 3
/2 log 3
x = -1
View Tag Cloud