evaluate: log(2)1/16i got -2.3344

solve for x: e^(x-2)=10

i got 4.30 = x

solve for x: 2log(3)x - log(3)2 = log(3)8

i got x = 4

(note: I'm assuming that the (2) is for base 2)

(Log1/16)/(Log2)

-4

Ln(e^x-2)= ln10

x-2= ln10

x-2+2= 2.3025 + 2

x= 4.3025