Need help in solving the following quadratic equations to the power of three...

$x^3-y^3=35$
$x-y=5$

Pls explain or show any relevant working. Thanks in advance for your help.

2. What have you tried thus far?

3. Use substitution. Solve the 2nd equation for x:
$x = y + 5$

Substitute this into the 1st equation for x:
\begin{aligned}
x^3 - y^3 &= 35 \\
(y + 5)^3 - y^3 &= 35 \\
y^3 + 15y^2 + 75y + 125 - y^3 &= 35 \\
15y^2 + 75y + 125 &= 35 \\
15y^2 + 75y + 90 &= 0
\end{aligned}

Solve this quadratic (you'll get two answers for y). Plug both into the equation
$x = y + 5$
to find the corresponding x values.