1. ## Distance and Velocity

A stone is dropped into a well and the report of the stone striking the bottom is heard 7.7 seconds after it is dropped. Assume that the stone falls 16t squared feet in t seconds and that the velocity of sound is 1,120 feet per second. The depth of the well is:

Help pls.

2. How can something fall an amount of squared feet per unit time? Falling = height = 1 dimension.

3. Originally Posted by Veronica1999
A stone is dropped into a well and the report of the stone striking the bottom is heard 7.7 seconds after it is dropped. Assume that the stone falls 16 (t squared) feet in t seconds and that the velocity of sound is 1,120 feet per second. The depth of the well is:

Help pls.
1. Per definition $\displaystyle distance = speed \cdot time$.

2. The total time is split into two parts: The time t which is needed by the falling stone and the remaining time (7.7 - t) which is needed by the sound. The falling stone and the sound have to pass the same distance d:

$\displaystyle d_{stone} = 16 \cdot t^2$

$\displaystyle d_{sound} = 1120 \cdot (7.7-t)$

3. Solve for t:

$\displaystyle 16 \cdot t^2 = 1120 \cdot (7.7-t)$

4. Plug in the value of t into one of the equations determining d to get the depth of the well.
Spoiler:
I've got 784 '

4. Thank you. Thank you. Thank you.
Everything is so clear now.