There is no right answer to 4, it should be |x|sqrt(y), as by convention sqrt()
is positive (for real positive argument), so sqrt(x^2 y) is by convention
positive, but x sqrt(y) has the same sign as x.
There is no right answer to 4, it should be |x|sqrt(y), as by convention sqrt()
is positive (for real positive argument), so sqrt(x^2 y) is by convention
positive, but x sqrt(y) has the same sign as x.
RonL
ah yes. my bad. sqrt(x^2) = |x| by definition. you know that mistake messed me up in a proof class once, lost like 5 points, i should remember that