Hey guys, I'm having trouble factorising this following: 8x^6 + 64 I've done the following: 8(x^6 + 8) I'm not sure how to factorise this further. Please provide detailed steps so I can understand. Thank you.
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Use the sum of two cubes rule $\displaystyle a^3 + b^3 = (a + b)(a^2 - ab + b^2)$. In your case, $\displaystyle 8(x^6 + 8) = 8[(x^2)^3 + 3^3]$.
Thank you so much! I've been struggling with math, and any help is greatly appreciated!
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