Results 1 to 2 of 2

Math Help - Finding a couple of intercepts and stuff

  1. #1
    Junior Member
    Joined
    Jun 2010
    Posts
    50

    Finding a couple of intercepts and stuff

    The first is 2x-1=y

    Simple enough: y=0, and say x=1. Then two minus one equals 1 for (1,0)

    Now x=0 so it's -1 divided by y for negative 1 for (0,-1).

    These create a straight line that graphs perfectly.

    1. I am doing this right, right?

    2. My second issue here is that I can't find a checkpoint for the above to save my life. Nothing makes sense... which in turn leads me to believe I'm not doing this right.

    Please help. Thank you.

    Oh, also: Graph 3y=-5

    I understand y=3 or x=1, but I don't get how and why a horizontal line below the x-axis is formed from this. There's no explanation in the book and it wasn't covered in class today. Homework for this section gets turned in right before the test for this section on Tuesday when we come back from the weekend.

    Again, thank you for your help. It is greatly appreciated.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by Ingersoll View Post
    The first is 2x-1=y

    Simple enough: y=0, and say x=1. Then two minus one equals 1 for (1,0) Mr F says: When y = 0, x = 1/2. (2x - 1 = 0 => 2x = 1 => x = 1/2).

    Now x=0 so it's -1 divided by y for negative 1 for (0,-1).

    These create a straight line that graphs perfectly.

    1. I am doing this right, right?

    2. My second issue here is that I can't find a checkpoint for the above to save my life. Nothing makes sense... which in turn leads me to believe I'm not doing this right.

    Please help. Thank you.

    Oh, also: Graph 3y=-5 Mr F says: Is this the complete equation? As written, y - -5/3 which is a horizontal line passing through y = -5/3.

    I understand y=3 or x=1, but I don't get how and why a horizontal line below the x-axis is formed from this. There's no explanation in the book and it wasn't covered in class today. Homework for this section gets turned in right before the test for this section on Tuesday when we come back from the weekend.

    Again, thank you for your help. It is greatly appreciated.
    I suggest you go back and review how to solve linear equations.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Finding X-Intercepts
    Posted in the Algebra Forum
    Replies: 4
    Last Post: October 11th 2011, 07:08 AM
  2. finding X & Y intercepts
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: January 31st 2011, 08:38 PM
  3. Need help finding the x-intercepts
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: April 3rd 2009, 05:20 PM
  4. Finding x and y intercepts
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: April 27th 2008, 12:53 PM
  5. Finding Intercepts
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: April 22nd 2008, 05:34 PM

Search Tags


/mathhelpforum @mathhelpforum