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- Jun 30th 2010, 11:00 AM #1

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- Jun 30th 2010, 11:24 AM #2

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- Jun 30th 2010, 12:05 PM #3

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- Jun 30th 2010, 02:07 PM #4

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- Jul 1st 2010, 05:50 AM #5
Please ... don't do that again: You can't measure a volume by a unit of length.

1. Volume of the milk crate: $\displaystyle V_{mc} = 50 cm \cdot 40 cm \cdot 20 cm = 40,000 cm^3$

2. Volume of the space on the vehicle: $\displaystyle V_{sv} = 2 m \cdot 1.6 m \cdot 1 m = 3.2 m^3$

3. You have to convert the units to use the values in the following calculations. Since $\displaystyle 1 m^3 = 1,000,000 cm^3$ you'll get $\displaystyle V_{sv} = 3,200,000 cm^3$

4. And now you can check by division how many crates fit into the space on the vehicle. (See p0oint's calculation)