Quote from a textbook:

Well, if $\displaystyle n\log n$ is presented as $\displaystyle n^x$, then what is $\displaystyle x$?... $\displaystyle n^{1.26}$ is asymptotically still greater than $\displaystyle n\log n$.

Or, if there is no such general representation, what would $\displaystyle x$ be for $\displaystyle n = 100, 1000, ...$ ($\displaystyle \log$ is base $\displaystyle 2$)?

I should've plotted first. "Solved" I guess.