# n*log(n) asymptotic behaviour

... $n^{1.26}$ is asymptotically still greater than $n\log n$.
Well, if $n\log n$ is presented as $n^x$, then what is $x$?
Or, if there is no such general representation, what would $x$ be for $n = 100, 1000, ...$ ( $\log$ is base $2$)?