Hello Guys first I want to thank the very smart people in here. I only wish you guys could be live to show me how to do some of this stuff.
5/4 (x-1/2) - 5/3 <4/3
{X/X __ __}
Please show me how to do this problem. Thank you very much.
Hello Guys first I want to thank the very smart people in here. I only wish you guys could be live to show me how to do some of this stuff.
5/4 (x-1/2) - 5/3 <4/3
{X/X __ __}
Please show me how to do this problem. Thank you very much.
At the moment this is unreadable.
I can't tell if the inequality is
$\displaystyle \frac{5}{4}\left(x - \frac{1}{2}\right) - \frac{5}{3} < \frac{4}{3}$
or
$\displaystyle \frac{5}{4\left(x - \frac{1}{2}\right)} - \frac{5}{3} < \frac{4}{3}$.
Please use brackets where they're needed or else learn LaTeX typesetting.
Hi, OneidaFL!
I guess it's this:::
$\displaystyle \displaystyle{\frac{5}{4} \left(x - \frac{1}{2}\right) - \left(\frac{5}{3}\right) < \frac{4}{3} }$
$\displaystyle [calculate-the-lowest-common-multiple-(LCM) = 12]$
$\displaystyle \displaystyle{\frac{ 15 (12x - 6) - 20}{12} < \frac{16}{12} } $
$\displaystyle ['cut'-the-equal-denominators-and-make-the-count!]$
$\displaystyle 15 (12x - 6) - 20 < 16 $
$\displaystyle 180x - 90 - 20 < 16 $
$\displaystyle 180x < 16 + 90 + 20 $
$\displaystyle 180x < 126 $
$\displaystyle x < \displaystyle{\frac{126}{180}}$
$\displaystyle x < \displaystyle{\frac{7}{10}}$
PS: I just didn't understand what's:::
IF it's{X/X __ __}
$\displaystyle \displaystyle{\frac{x}{x} } = 1$
$\displaystyle because$
$\displaystyle x < \displaystyle{\frac{7}{10}}$
$\displaystyle \displaystyle{\frac{7}{10}} : \displaystyle{\frac{7}{10}} = \displaystyle{\frac{70}{70}} \Rightarrow 1$
Hope It helps!