Given $\displaystyle log_3{7}=1.771$ and $\displaystyle log _3{5}=1.465$.find

a)$\displaystyle log_9{35}$

this is my step:

$\displaystyle =log{_\sqrt{9}}35^\frac{1}{2}$

$\displaystyle =\frac{1}{2}log_3(5)(7)$

$\displaystyle =\frac{1}{2}log_3{5}+log_3{7}$

$\displaystyle =\frac{1}{2}(1.465)+(1.771)$

$\displaystyle =2.5035$