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Math Help - Completing The Square

  1. #1
    Junior Member alwaysalillost's Avatar
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    Post Completing The Square

    Complete the square.

    1. x^2 + 12x + ______

    2. x^2 - 6x + ______

    Solve by completing the square.

    3. x^2 - 6x = 16

    4. 2x^2 - 3x + 1 = 0

    5. x^2 - 4x - 5 = 0
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by alwaysalillost View Post
    Complete the square.

    1. x^2 + 12x + ______

    2. x^2 - 6x + ______
    i suppose for these two questions you just want us to add the constant that will make each a complete square. so i will do that.

    in the expanded form of complete squares, the lone constant is always the square of half the coefficient of x.

    1. x^2 + 12x + (12/2)^2 will give a complete square.
    => x^2 + 12x + 6^2
    => (x + 6)^2 is the completed square

    2. x^2 - 6x + (-6/2)^2
    => x^2 - 6x + (-3)^2
    => (x - 3)^2 is the completed square.



    Solve by completing the square.

    3. x^2 - 6x = 16
    now since we are in an equation, adding constants have consequences. now when we add something, we have to add it to the other side as well. before we add anything, we want to make sure that the coefficient of x^2 is one, so we are ok here.

    x^2 - 6x + (-3)^2 = 16 + (-3)^2
    => (x - 3)^2 = 16 + 9
    => (x - 3)^2 = 25
    => x - 3 = +/- sqrt(25)
    => x = 3 +/- sqrt(25) = 3 +/- 5
    => x = 8 or x = -2


    why don't you try the rest to see if you get it. i didn't go into detail about completing the square, so i don't know if you're understanding the process
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  3. #3
    Junior Member alwaysalillost's Avatar
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    Thanks Jhevon. I'll try to do the others on my own. Thanks again.
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by alwaysalillost View Post
    Thanks Jhevon. I'll try to do the others on my own. Thanks again.
    ok. don't be afraid to ask for help if you're having trouble with the rest
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  5. #5
    Junior Member alwaysalillost's Avatar
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    2x^2 - 3x + 1 = 0
    x^2 - 3/2x + 1/2 = 0
    x^2 - 3/2x + 9/16 = 1/16
    (x - 3/4)^2 = 1/16
    (x-3/4) = 1/4, -1/4
    x = 1/4 + 3/4, -1/4 + 3/4
    x = 1, 1/2

    Would this be the right answer to number four?
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by alwaysalillost View Post
    2x^2 - 3x + 1 = 0
    x^2 - 3/2x + 1/2 = 0
    x^2 - 3/2x + 9/16 = 1/16
    (x - 3/4)^2 = 1/16
    (x-3/4) = 1/4, -1/4
    x = 1/4 + 3/4, -1/4 + 3/4
    x = 1, 1/2

    Would this be the right answer to number four?
    You are correct, good job!!!

    your steps seem weird though. all the numbers are correct, but the way you did it, you can't really see the process...but who cares! if you know what your are doing, and you get the right answer and the method is reasonable, you're good!

    there are more right? try the rest
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