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Math Help - Exponential Form

  1. #1
    Junior Member alwaysalillost's Avatar
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    Exponential Form

    Write each of the following in exponential form.


    Any help is appreciated!
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    Re:

    Quote Originally Posted by alwaysalillost View Post
    Write each of the following in exponential form.


    Any help is appreciated!
    Hi Alwaysalillost!

    Writing these in exponential form is a piece of cake...
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    Last edited by qbkr21; May 13th 2007 at 11:50 AM.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by alwaysalillost View Post
    Write each of the following in exponential form.


    Any help is appreciated!
    Do you like flowers, alwaysalillost? becuase thinking of flowers is the easiest way to do this. It may seem cheezy to you, but to this day, I use this rule to double check myself that I am changing from exponents to roots and vice versa correctly.

    It is known as Flower Power!

    Basically, we equate a fractional exponent to a flower. The top number represents the flower (which rhymes with power) and the bottom number represents the root, and the division sign represents the ground. So now we know that whenever we have a fractional exponent, the top number is the power of the base and the bottom number is the root of the base.


    so sqrt(x) = x^(1/2) because the power of x is 1, and the root we are using is the 2nd root.

    fourthroot(2) = 2^(1/4), since the power of 2 is 1 and the root is the fourth

    the cuberoot(x^2*y^3) = cuberoot(x^2)*cuberoot(y^3) by the law of surds.

    now cuberoot(x^2) = x^(2/3) since the (flower) power of x is 2 so it goes on top, and the root is the third root, so it goes on the bottom.

    and cuberoot(y^3) = y^(3/3) since the power of y is 3 and the root of y is 3, so we get y^1 or just y

    therefore, cuberoot(x^2*y^3) = cuberoot(x^2)*cuberoot(y^3) = (x^(2/3))*y


    Note: we can take the root or the power first.

    that is, for example, if we have x^(2/3) we can write it as cuberoot(x^2) or [cuberoot(x)]^2 depending on which woud be easier to calculate. if you want an example of when one would be easier than the other, ask
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Sorry qbkr21, I saw you answered this after I posted my solution, this took me forever to draw in paint, so i never saw the thread for a long time
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  5. #5
    Junior Member alwaysalillost's Avatar
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    Thanks Jhevon & qbkr21!
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