1. ## Some algebra

Here is the question:

I've done part a), however in part b) I'm confused as how to get rid of the modulus..

Any help is appreciated!

Thanks

After making part a), you'll see that there are two points of intersection.

First, solve for x being positive, rejecting one value. Your diagram would tell you which one to reject.
Then, do the same thing with the negative value of x.

Finally, you should get

x = 2

$x = \frac14(-1-\sqrt{17})$

3. Originally Posted by Unknown008

After making part a), you'll see that there are two points of intersection.

First, solve for x being positive, rejecting one value. Your diagram would tell you which one to reject.
Then, do the same thing with the negative value of x.

Finally, you should get

x = 2

$x = \frac14(-1-\sqrt{17})$

I got both results thanks!

4. You're welcome