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Math Help - Some algebra

  1. #1
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    Some algebra

    Here is the question:

    Some algebra-screen-shot-2010-06-24-19.16.45.png

    I've done part a), however in part b) I'm confused as how to get rid of the modulus..

    Any help is appreciated!

    Thanks
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  2. #2
    MHF Contributor Unknown008's Avatar
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    You should use your diagram you made in a) to help you.

    After making part a), you'll see that there are two points of intersection.

    First, solve for x being positive, rejecting one value. Your diagram would tell you which one to reject.
    Then, do the same thing with the negative value of x.

    Finally, you should get

    x = 2

    x = \frac14(-1-\sqrt{17})
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  3. #3
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    Quote Originally Posted by Unknown008 View Post
    You should use your diagram you made in a) to help you.

    After making part a), you'll see that there are two points of intersection.

    First, solve for x being positive, rejecting one value. Your diagram would tell you which one to reject.
    Then, do the same thing with the negative value of x.

    Finally, you should get

    x = 2

    x = \frac14(-1-\sqrt{17})

    I got both results thanks!
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  4. #4
    MHF Contributor Unknown008's Avatar
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    You're welcome
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