Here is the question:

Attachment 17986

I've done part a), however in part b) I'm confused as how to get rid of the modulus..

Any help is appreciated!

Thanks

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- June 24th 2010, 11:18 AMmaggiecSome algebra
Here is the question:

Attachment 17986

I've done part a), however in part b) I'm confused as how to get rid of the modulus..

Any help is appreciated!

Thanks - June 24th 2010, 11:37 AMUnknown008
You should use your diagram you made in a) to help you.

After making part a), you'll see that there are two points of intersection.

First, solve for x being positive, rejecting one value. Your diagram would tell you which one to reject.

Then, do the same thing with the negative value of x.

Finally, you should get

x = 2

- June 24th 2010, 12:07 PMmaggiec
- June 24th 2010, 12:11 PMUnknown008
You're welcome(Happy)