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Thread: Fraction inside a square root. need some help

  1. June 23rd 2010, 08:35 PM #1
    coryjannis
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    Fraction inside a square root. need some help

    haven't taken math in a while and I'm taking a trigonometry class. I believe i learned this in algebra but i can't remember how its done.

    cos = +/-√1-225/289

    (basically i don't understand how to do the square root part of this. its the square root of 1- 225 over 289.

    The answer for this is = +/- 8/17

    **no clue how they got 8/17.
    thx and godbless if anybody can help me

    http://i48.photobucket.com/albums/f2...799/sqroot.jpg
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  2. June 23rd 2010, 08:53 PM #2
    pickslides
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    \sqrt{1-\frac{225}{289} }=\sqrt{\frac{289}{289}-\frac{225}{289} }= \sqrt{\frac{64}{289} }=\frac{ \sqrt{64}}{\sqrt{289}} = \pm \frac{8}{17}
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