A Cubic Polynomial with integral coefficients has a root and possesses the form:

Find AB/25

Have no clue where to start with this one. Any help is appreciated.

Printable View

- Jun 23rd 2010, 06:25 AMrtblueCubic Polynomial
A Cubic Polynomial with integral coefficients has a root and possesses the form:

Find AB/25

Have no clue where to start with this one. Any help is appreciated. - Jun 23rd 2010, 06:41 AMAckbeet
If you know one root, you should be able to factor the cubic. One way to do that is by polynomial long division. The result should look like your y.

- Jun 23rd 2010, 06:52 AMrtblue
How can I factor the polynomial, if the A and B values are not given? On another note, If one of the roots of the polynomial is (3-4i), then another root has to be (3+4i). multiplication of the two gives us

Now where do I go from here? - Jun 23rd 2010, 07:05 AMp0oint
You found that well.

Now just do this (x-(3-4i))(x-(3+4i) or

Regards. - Jun 23rd 2010, 07:33 AMUnknown008
Well, I tried using the factor theorem.

Let

Since 3-4i is a factor, f(3-4i) = 0.

So,

Expanding, you get:

So,

and

I'm not sure if that's right though (Thinking)

This gives a = -11, and b = 150

So, - Jun 23rd 2010, 11:01 AMHallsofIvy