Thread: System of equations with 3 variables

x + ky=1
kx - 3ky = 2k+3

We can assume that k is a parameter, now you solve it becomes a two equitation with two variables x and y.

Now we solve it,

multiply the first equation by 3 and add to the second one.
You get:
3x + 3ky +kx-3ky=3+2k+3
3x +kx=6+2k
x(3+k)=2(3+k)
x=3


I let you find y...

Originally Posted by Also sprach Zarathustra

...
3x +kx=6+2k
x(3+k)=2(3+k)
x=3 <<<<<<<<<<< typo


I let you find y...

hmmm ...

Originally Posted by earboth

hmmm ...

yes, thanks, I'm sorry