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Math Help - [SOLVED] If a=0.2, find the value of

  1. #1
    Newbie adhiluhur's Avatar
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    [SOLVED] If a=0.2, find the value of

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  2. #2
    MHF Contributor undefined's Avatar
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    I haven't seen this typesetting before, but I'm assuming we want

    \left(2^{\log_26} \right)\left(3^{\log_95} \right)\left(5^{\log_a2} \right)

    (Edited)

    The middle factor can be evaluated as follows.

    3^{\log_95}=3^{\frac{\log_35}{\log_39}}=3^{\frac{1  }{2}\cdot\log_35}=\left( 3^{\log_35}\right)^{\left(\frac{1}{2}\right)}=\sqr  t{5}
    Last edited by undefined; June 11th 2010 at 03:57 AM.
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  3. #3
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    Quote Originally Posted by adhiluhur View Post
    There is no equation. Find the value of what?
    Whether the expression is 2^{2log6} and so on?
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  4. #4
    Newbie adhiluhur's Avatar
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    Quote Originally Posted by sa-ri-ga-ma View Post
    There is no equation. Find the value of what?
    Whether the expression is 2^{2log6} and so on?
    Sorry for the misunderstanding.
    I mean
    Please find the value of "..."
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  5. #5
    Newbie adhiluhur's Avatar
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    Quote Originally Posted by undefined View Post
    I haven't seen this typesetting before, but I'm assuming we want

    \left(2^{\log_26} \right)\left(3^{\log_95} \right)\left(5^{\log_a2} \right)

    (Edited)

    The middle factor can be evaluated as follows.

    3^{\log_95}=3^{\frac{\log_35}{\log_39}}=3^{\frac{1  }{2}\cdot\log_35}=\left( 3^{\log_35}\right)^{\left(\frac{1}{2}\right)}=\sqr  t{5}
    yes people in my country use this kind of typesetting, however people in europe use like yours.
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  6. #6
    Newbie adhiluhur's Avatar
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    Hey. the first factor is 6.
    the second is root 5
    anyone can solve the third so that we can find the value of the equation?
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  7. #7
    Newbie adhiluhur's Avatar
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    YEAH I got the third!
    Thanks to "undefined" I can get the value of third factor by imitating your steps.



    Therefore

    6 * root 5 * 0.5 = 3 root 5

    SOLVED!!
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