# Thread: [SOLVED] If a=0.2, find the value of

1. ## [SOLVED] If a=0.2, find the value of

2. I haven't seen this typesetting before, but I'm assuming we want

$\left(2^{\log_26} \right)\left(3^{\log_95} \right)\left(5^{\log_a2} \right)$

(Edited)

The middle factor can be evaluated as follows.

$3^{\log_95}=3^{\frac{\log_35}{\log_39}}=3^{\frac{1 }{2}\cdot\log_35}=\left( 3^{\log_35}\right)^{\left(\frac{1}{2}\right)}=\sqr t{5}$

There is no equation. Find the value of what?
Whether the expression is $2^{2log6}$ and so on?

4. Originally Posted by sa-ri-ga-ma
There is no equation. Find the value of what?
Whether the expression is $2^{2log6}$ and so on?
Sorry for the misunderstanding.
I mean
Please find the value of "..."

5. Originally Posted by undefined
I haven't seen this typesetting before, but I'm assuming we want

$\left(2^{\log_26} \right)\left(3^{\log_95} \right)\left(5^{\log_a2} \right)$

(Edited)

The middle factor can be evaluated as follows.

$3^{\log_95}=3^{\frac{\log_35}{\log_39}}=3^{\frac{1 }{2}\cdot\log_35}=\left( 3^{\log_35}\right)^{\left(\frac{1}{2}\right)}=\sqr t{5}$
yes people in my country use this kind of typesetting, however people in europe use like yours.

6. Hey. the first factor is 6.
the second is root 5
anyone can solve the third so that we can find the value of the equation?

7. YEAH I got the third!
Thanks to "undefined" I can get the value of third factor by imitating your steps.

Therefore

6 * root 5 * 0.5 = 3 root 5

SOLVED!!