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Math Help - Multiplying expressions?

  1. #1
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    Multiplying expressions?

    Little foggy on this ...How do u approach it? (a-b) * ((a-c)/2b)
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  2. #2
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    Quote Originally Posted by oshow View Post
    Little foggy on this ...How do u approach it? (a-b) * ((a-c)/2b)
    When multiplying fractions by any number, you multiply the number with the numerator of the fraction.
    So here our 'number' is (a-b), and then (a-b) * ((a-c)/2b) would be:

    ?
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  3. #3
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    Quote Originally Posted by oshow View Post
    Little foggy on this ...How do u approach it? (a-b) * ((a-c)/2b)
    \frac{{(a - b)(a - c)}}<br />
{{2b}}
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  4. #4
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    I have this ((a-b) (a-c))/2b but for the final answer they have (a+c)/2...How do we get here?
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  5. #5
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    Quote Originally Posted by oshow View Post
    I have this ((a-b) (a-c))/2b but for the final answer they have (a+c)/2...How do we get here?
    That is impossible if you have given the correct problem.
    There is a typo somewhere.
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  6. #6
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    Sorry...the equation is (a-b) ((a-c)/2b)....and the final answer is (a+c)/2...How do we get here?
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  7. #7
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    Quote Originally Posted by oshow View Post
    the equation is (a-b) ((a-c)/2b)....and the final answer is (a+c)/2...How do we get here?
    There is absolutely no point in reposting the same question.
    You have been told that the must be a typo some where.
    It is impossible to derive that answer from that expression.
    Is there more to the problem that you have told us?
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  8. #8
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    (a-b) *((a-c)/2b)= P
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  9. #9
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    Quote Originally Posted by oshow View Post
    (a-b) *((a-c)/2b)= P
    I even tried messing around with the parentheses, and it just dont make any sense, so there indeed must be a typo somewhere. Please post the whole question

    Kind regards
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