1. ## Multiplying expressions?

Little foggy on this ...How do u approach it? (a-b) * ((a-c)/2b)

2. Originally Posted by oshow
Little foggy on this ...How do u approach it? (a-b) * ((a-c)/2b)
When multiplying fractions by any number, you multiply the number with the numerator of the fraction.
So here our 'number' is (a-b), and then (a-b) * ((a-c)/2b) would be:

?

3. Originally Posted by oshow
Little foggy on this ...How do u approach it? (a-b) * ((a-c)/2b)
$\displaystyle \frac{{(a - b)(a - c)}} {{2b}}$

4. I have this ((a-b) (a-c))/2b but for the final answer they have (a+c)/2...How do we get here?

5. Originally Posted by oshow
I have this ((a-b) (a-c))/2b but for the final answer they have (a+c)/2...How do we get here?
That is impossible if you have given the correct problem.
There is a typo somewhere.

6. Sorry...the equation is (a-b) ((a-c)/2b)....and the final answer is (a+c)/2...How do we get here?

7. Originally Posted by oshow
the equation is (a-b) ((a-c)/2b)....and the final answer is (a+c)/2...How do we get here?
There is absolutely no point in reposting the same question.
You have been told that the must be a typo some where.
It is impossible to derive that answer from that expression.
Is there more to the problem that you have told us?

8. (a-b) *((a-c)/2b)= P

9. Originally Posted by oshow
(a-b) *((a-c)/2b)= P
I even tried messing around with the parentheses, and it just dont make any sense, so there indeed must be a typo somewhere. Please post the whole question

Kind regards