hi guys how do expand this log expression?
log(3��² √��/³√5��²)
Applying the rules of logarithms
$\displaystyle \log\left(\frac{3x^2\sqrt{y}}{\sqrt[3]{5}z^2}\right)$
$\displaystyle =\log(3x^2\sqrt{y})-\log(\sqrt[3]{5}z^2)$
$\displaystyle =\log(3)+\log(x^2)+\log(y^{\frac{1}{2}})-\log(5^{\frac{1}{3}})-\log(z^2)$
$\displaystyle =\log(3)+2\cdot\log(x)+\frac{1}{2}\cdot\log(y)-\frac{1}{3}\cdot\log(5)-2\cdot\log(z)$