here it is:
(z)/[(y+21)/(x+5.5)]=(3.1)/(y/x)
I'm trying to find z. It's supposed to be my gpa so somewhere between 3.0 and 3.7 I have been at it for a long time. someone help me please, it's my first post!
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here it is:
(z)/[(y+21)/(x+5.5)]=(3.1)/(y/x)
I'm trying to find z. It's supposed to be my gpa so somewhere between 3.0 and 3.7 I have been at it for a long time. someone help me please, it's my first post!
What are x and y? You can solve for z in terms of x and y, but you won't be able to say it's a number between 3.0 and 3.7 unless you can plug in x and y.Quote:
Originally Posted by monzer13
I don't have X or Y. I just know it falls into that range because my GPA was a 3.1 at the end of the year and I got 4 A's and 2 B's, so it should've gone up.
You won't be able to solve in this manner without more information. GPA's are calculated by taking [sum of ((course grade value) * (course credit hours))] / (total credit hours), so it's a weighted average. For example, if biology is worth 3 credit hours and chemistry is worth 2, then an A (4.0) in biology will count more towards the GPA than an A in chemistry. And even if all your courses have the same credit hours, it's still true that: the more accumulated credit hours that went into your GPA of 3.1, the less your newer grades will affect your GPA (because the previous GPA's weight will be large compared with the weights of the new courses).Quote:
Originally Posted by monzer13
If you need an illustration:
The average of (1,4,3) is 8/32.67. If you add on another 4, then you have the average of (1,4,3,4) is 3. (It changed substantially.)
The average of (1,4,3,4,1,2,3,4,2,3,4,1,2,3,2,3,1,4,4,4,2) is 19/7
Ok well, I have a 3.1 gpa. I received 5.5 credit hours this year and I got a 21 total for my grades. (3*4 a's + 3*3 B's = 21) Am I able to calculate my current cumulative GPA now? I know my current for this year is 21/5.5=3.82