Results 1 to 3 of 3

Math Help - Solving for unknown

  1. #1
    Super Member
    Joined
    Dec 2009
    Posts
    755

    Solving for unknown

    solve for x in  <br />
2^{x+1}-24\sqrt{2^x}+64=0<br />
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Sep 2008
    From
    West Malaysia
    Posts
    1,261
    Quote Originally Posted by Punch View Post
    solve for x in  <br />
2^{x+1}-24\sqrt{2^x}+64=0<br />
    the easiest way is to let 2^x be an unknown, then factorise the equation and replace the solutions back with 2^x.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor undefined's Avatar
    Joined
    Mar 2010
    From
    Chicago
    Posts
    2,340
    Awards
    1
    Quote Originally Posted by Punch View Post
    solve for x in  <br />
2^{x+1}-24\sqrt{2^x}+64=0<br />
     2^{x+1}-24\sqrt{2^x}+64=0

    2\cdot2^x-24\cdot2^{\frac{x}{2}}+64=0

    Let y=2^{\frac{x}{2}}

    2y^2-24y+64=0

    Solve the quadratic for y, then go back and find x.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Solving unknown values.
    Posted in the Algebra Forum
    Replies: 3
    Last Post: January 15th 2012, 10:46 AM
  2. Solving for an unknown variable
    Posted in the Algebra Forum
    Replies: 1
    Last Post: September 19th 2011, 03:40 PM
  3. Solving for unknown varilable
    Posted in the Algebra Forum
    Replies: 2
    Last Post: February 5th 2011, 11:08 AM
  4. Need help solving an unknown
    Posted in the Algebra Forum
    Replies: 3
    Last Post: May 10th 2010, 07:23 AM
  5. Solving the Unknown for Indices
    Posted in the Algebra Forum
    Replies: 7
    Last Post: May 2nd 2009, 02:03 AM

Search Tags


/mathhelpforum @mathhelpforum