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Math Help - inequalities

  1. #1
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    inequalities

    8 < x < 12

    12 < y < 15

    if x and y are integers that satisfy the conditions above , what is one possible value of xy ?
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  2. #2
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    Pick some numbers, here's a possibility x= 9, y= 13,9\times 13 = \dots
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  3. #3
    Junior Member lanierms's Avatar
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    Since x and y are integers,
    x=\{9,10,11\}
    y=\{13,14\}
    So there can be six values of xy.
    xy=9\times 13
    or
    xy=9\times 14
    or
    xy=10\times 13
    or
    xy=10\times 14
    or
    xy=11\times 13
    or
    xy=11\times 14
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  4. #4
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    How about this?

    96 < xy < 180
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  5. #5
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    Quote Originally Posted by wonderboy1953 View Post
    96 < xy < 180
    Nope, 118 is on that interval and not a solution.
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