1) divide by cos(x) both sides
2) subtract 1 on both sides then use the equality cos^2(x)=1-sin^(x)
3) cos(2x)=cos^2(x)-sin^2(x) and 1=sin^2(x)+cos^2(x)
Please help me to solve the following equations (giving 1 or 2 solutions):
sin x = √3 cos x
sin^2x - cos^2x – sin x = 1
cos 2x + sin x + 1 = 0
sin 2 x + cos x = 0
tan^2x + sec x – 1 = 0
Any help no matter how little is much appreciated, I just don't know where to start.
Thanks in advance.