1. ## Exponent Help

I need help solving for x

4X6^3x+4 = 864

Originally Posted by Gomaz23
I need help solving for x

4X6^3x+4 = 864
first this could mean

$4(6)^{3x} +4 = 864$ or $4(6)^{3x+4} = 864$

assuming the last one

$4(6)^{3x+4} = 864 \Rightarrow 6^{3x+4} = 6^3 \Rightarrow 3x+4 = 3$ and then solve for $x$

$B^{m}B^{n} = B^{M+N}, \frac{B^m}{B^n} = B^{m-n}, (B^{m})^{n} =B^{mn}$

3. but the thing is how am i supposed to solve for x?

4. Originally Posted by Gomaz23
but the thing is how am i supposed to solve for x?
just do the remaining algrebra

from $3x+4=3$

subtract $4$ from both sides, then

$
3x = -1$

divide both sides by $3$, then

$x= -\frac{1}{3}$

EDIT: sorry kept getting my latex typed wrong