Results 1 to 4 of 4

Math Help - Exponent Help

  1. #1
    Newbie
    Joined
    Oct 2008
    Posts
    19

    Exponent Help

    I need help solving for x


    4X6^3x+4 = 864
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580

    Cool added exponent laws

    Quote Originally Posted by Gomaz23 View Post
    I need help solving for x


    4X6^3x+4 = 864
    first this could mean

    4(6)^{3x} +4 = 864 or 4(6)^{3x+4} = 864

    assuming the last one

    4(6)^{3x+4} = 864 \Rightarrow 6^{3x+4} = 6^3 \Rightarrow 3x+4 = 3 and then solve for x

    B^{m}B^{n} = B^{M+N},  \frac{B^m}{B^n} = B^{m-n}, (B^{m})^{n} =B^{mn}
    Last edited by bigwave; June 7th 2010 at 03:12 PM. Reason: assuming the last one
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Oct 2008
    Posts
    19
    but the thing is how am i supposed to solve for x?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580
    Quote Originally Posted by Gomaz23 View Post
    but the thing is how am i supposed to solve for x?
    just do the remaining algrebra

    from 3x+4=3

    subtract 4 from both sides, then

     <br />
3x = -1

    divide both sides by 3, then

    x= -\frac{1}{3}

    EDIT: sorry kept getting my latex typed wrong
    Last edited by bigwave; June 7th 2010 at 03:06 PM. Reason: latex
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: April 27th 2011, 04:53 PM
  2. exponent
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: May 31st 2010, 08:25 AM
  3. [SOLVED] Help dividing exponent by exponent
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 29th 2010, 11:20 AM
  4. -1 to an exponent
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: August 19th 2009, 09:36 AM
  5. Replies: 1
    Last Post: August 19th 2008, 08:41 AM

Search Tags


/mathhelpforum @mathhelpforum