I need help solving for x
4X6^3x+4 = 864
first this could mean
$\displaystyle 4(6)^{3x} +4 = 864$ or $\displaystyle 4(6)^{3x+4} = 864$
assuming the last one
$\displaystyle 4(6)^{3x+4} = 864 \Rightarrow 6^{3x+4} = 6^3 \Rightarrow 3x+4 = 3$ and then solve for $\displaystyle x$
$\displaystyle B^{m}B^{n} = B^{M+N}, \frac{B^m}{B^n} = B^{m-n}, (B^{m})^{n} =B^{mn}$