I am trying to solve the following equation for Tc (Temperature in celsius).

So far I was able to generate this equation from an expression I found online.

RH = 9.5exp(-17.29Tc/Tc+238.3°)*(10.5°C-Tc)%

1). ln(RH/9.5) = ln(e(-17.27Tc/Tc+238.3°)*(10.5°C-Tc))

2). ln(RH/9.5) = ((-17.27Tc/Tc+238.3°)*(10.5°C-Tc))lne ; lne = 1

3). ln(RH/9.5) = (-17.27Tc)/((10.5°C-Tc)*(Tc+100°C)) ; 238.3° = 100°C

How to solve resulting quadratic for Tc??

Snow at above freezing temperatures | ScienceBits

scroll down and find the equation for RH. Can you solve for Tc?

Thanks,

Rick