hello i am trying to solve this equation for the values of x. can i get some help solving this one.
$\displaystyle
3^{2x-1} -4(3^x) + 1= 0
$
Hi sigma1,
$\displaystyle 3^{2x-1} -4(3^x) + 1= 0$
$\displaystyle 3^{-1}3^{2x} -4(3^x) + 1= 0$
$\displaystyle \left(\frac{1}{3}\right)\left(3^{x}\right)^2 -4(3^x) + 1= 0$
$\displaystyle \left(\frac{1}{3}\right)y^2 -4y + 1= 0$
$\displaystyle y^2-12y+3=0$
where $\displaystyle y = 3^x$.