what is the equation of the axis of symmetry for this function? y = ( x-3)(x-7)
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Originally Posted by ecdino2 what is the equation of the axis of symmetry for this function? y = ( x-3)(x-7) For parabolic equations this is always through the vertex. When the equation is in intecept form the vertex is always the midpoint of the x-intercepts. So for the above the vertical line is x=...
Originally Posted by ecdino2 what is the equation of the axis of symmetry for this function? y = ( x-3)(x-7) It's half way inbetween our zeros. So, $\displaystyle x_{sym} = \frac{ 7 + 3 }{2} = 5 $
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