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Math Help - Changing measurement

  1. #1
    Senior Member Mukilab's Avatar
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    Changing measurement

    Lets say I have two objects, Object A and Object B

    If A is of volume 100 and B is of 50. If I am asked to find the surface area of B if A is 20 can I just do it normally?

    Sorry, this is hard to say.

    Could I do it in this way: \frac{50}{100}=\frac{\text{surface area of B}}{20} ?

    Or do I have to mess around by changing the volume e.g. like you have to change it if you are given a volume in m^3 and you need it in cm^3?
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  2. #2
    MHF Contributor
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    Consider a cube : V = a^3 and S = a^2 therefore S^3/V^2 = constant

    You can make the same consideration for a sphere

    Note also that S^3 / V^2 has no unity

    Maybe you can use this to evaluate the surface of B
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  3. #3
    Senior Member Mukilab's Avatar
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    Yes but it's not volume divided by surface area of vice versa, its volume over volume in proportion to surface area over surface area
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