Does $\displaystyle 8^{\frac{1}{2}}=\sqrt{8}$ or $\displaystyle \frac{1}{8}$? Same with a negative fraction. Any tips?
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anything to the power of 1/2 is the square root of that base. 8^1/2 = square root of 8 anyting to the power of - means 1 over to that power 8^-1/2 = 1/ 8^2 = 1/64
Originally Posted by Joel anything to the power of 1/2 is the square root of that base. 8^1/2 = square root of 8 anyting to the power of - means 1 over to that power 8^-1/2 = 1/ 8^2 = 1/64 Thanks Great explanation
Wait, lets say I get 8^-2/3 would it be (2/8)^3???
Originally Posted by Mukilab Wait, lets say I get 8^-2/3 would it be (2/8)^3??? no as Joel said "anyting to the power of - means 1 over to that power" 8^-2/3 = 1/ 8^2/3
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