Following Mr Fantastic's previous advice I did Sub into the second equation
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Did it again and got a different answer y^2=9+2x^2 -y^2=x^2-18 Add them together to eliminate y 0=3x^2-9 9=3x^2
Originally Posted by Mukilab Following Mr Fantastic's previous advice I did No Expand and substitute into the 2nd equation to get a quadratic with x as unknown
y=4x^2+12x+9 Substituted 0=5x^2+12x-9
Yes Now you need to solve 0=5x^2+12x-9
yes but I get a horrendous equation along the lines of This is a no calculator paper. Maybe I should just use that?
Originally Posted by Mukilab yes but I get a horrendous equation along the lines of This is a no calculator paper. Maybe I should just use that? Are you kidding us? SQRT(324) = 18
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