Solve
\$\displaystyle \frac{3}{(y-1)^2}+\frac{3}{2(y-1)^2}=2$
I tried most things but get stuck at $\displaystyle \frac{9}{4}=(y-1)^2$ pretty much every time. Any help?
Don't ever be sorry for asking for help
$\displaystyle \pm \sqrt{\frac{9}{4}} = \pm \sqrt{\left(\frac{3}{2}\right)^2}$
As $\displaystyle \pm \sqrt{a^2} = \pm a$ that square root can be reduced
You should get $\displaystyle y = \pm \frac{3}{2} + 1$ hence $\displaystyle y = \frac{5}{2} \text{ or } y = -\frac{1}{2}$
We can't add the 1 under the square root since $\displaystyle \sqrt{a} + \sqrt{b} \neq \sqrt{a+b}$